# std::chrono::operator ==,!=,<,<=,>,>= (std::chrono::year_month_day)

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< cpp‎ | chrono‎ | year month day

constexpr bool operator==(const std::chrono::year_month_day & x, const std::chrono::year_month_day & y) noexcept; | (1) | (since C++20)
constexpr bool operator!=(const std::chrono::year_month_day & x, const std::chrono::year_month_day & y) noexcept; | (2) | (since C++20)
constexpr bool operator< (const std::chrono::year_month_day & x, const std::chrono::year_month_day & y) noexcept; | (3) | (since C++20)
constexpr bool operator> (const std::chrono::year_month_day & x, const std::chrono::year_month_day & y) noexcept; | (4) | (since C++20)
constexpr bool operator<=(const std::chrono::year_month_day & x, const std::chrono::year_month_day & y) noexcept; | (5) | (since C++20)
constexpr bool operator>=(const std::chrono::year_month_day & x, const std::chrono::year_month_day & y) noexcept; | (6) | (since C++20)

Compares the two `year_month_day` objects `x` and `y`. This is a lexicographical comparison: the year() is compared first, then month(), then day().

### Return value

1) x.year() == y.year() && x.month() == y.month() && x.day() == y.day()
2) !(x == y)
3) If x.year() != y.year(), x.year() < y.year(); otherwise if x.month() != y.month(), x.month() < y.month(); otherwise x.day() < y.day()
4) y < x
5) !(y < x)
6) !(x < y)

### Notes

If both `x` and `y` represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.

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